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Showing menu whenever mouse leaves document is too aggressive ... just using menuControl for now (see #94).

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Michael Jumper
2012-02-23 15:46:11 -08:00
parent 2e0ff46d6b
commit a0d81dbbba
1 changed files with 0 additions and 19 deletions
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19
guacamole/src/main/webapp/scripts/interface.js
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@@ -244,25 +244,6 @@ var GuacamoleUI = {
// Detect long-press at bottom of screen // Detect long-press at bottom of screen
document.body.addEventListener('touchstart', GuacamoleUI.startLongPressDetect, true); document.body.addEventListener('touchstart', GuacamoleUI.startLongPressDetect, true);
// Show menu if mouse leaves document
document.addEventListener('mouseout', function(e) {
// Get parent of the element the mouse pointer is leaving
if (!e) e = window.event;
var target = e.relatedTarget || e.toElement;
// Ensure target is not document nor child of document
var targetParent = target;
while (targetParent != null) {
if (targetParent == document) return;
targetParent = targetParent.parentNode;
}
// Start detection of intent to open menu
GuacamoleUI.startMenuOpenDetect();
}, true);
// Reconnect button // Reconnect button
GuacamoleUI.buttons.reconnect.onclick = function() { GuacamoleUI.buttons.reconnect.onclick = function() {
window.location.reload(); window.location.reload();